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Fix symbol visibility of init method

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This was properly an oversight when switching to the BOOST_SYMBOL_*
symbols from Boost.Config in commit 0224f54a (see #1)

Since Boost.Config is already doing the differentiation between
different platforms and compilers we can simplify this bit and just
use BOOST_SYMBOL_EXPORT
This commit is contained in:
Marvin Schmidt
2017-09-04 07:43:43 +02:00
committed by Stefan Seefeld
parent b09d80a93e
commit 9d2903cd5e
1 changed files with 3 additions and 19 deletions
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22
include/boost/python/module_init.hpp
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@@ -66,25 +66,9 @@ BOOST_PYTHON_DECL PyObject* init_module(char const* name, void(*)());
# endif
# if (defined(_WIN32) || defined(__CYGWIN__)) && !defined(BOOST_PYTHON_STATIC_MODULE)
# define BOOST_PYTHON_MODULE_INIT(name) \
void BOOST_PP_CAT(init_module_,name)(); \
extern "C" __declspec(dllexport) _BOOST_PYTHON_MODULE_INIT(name)
# elif BOOST_PYTHON_USE_GCC_SYMBOL_VISIBILITY
# define BOOST_PYTHON_MODULE_INIT(name) \
void BOOST_PP_CAT(init_module_,name)(); \
extern "C" __attribute__ ((__visibility__("default"))) _BOOST_PYTHON_MODULE_INIT(name)
# else
# define BOOST_PYTHON_MODULE_INIT(name) \
void BOOST_PP_CAT(init_module_,name)(); \
extern "C" _BOOST_PYTHON_MODULE_INIT(name)
# endif
# define BOOST_PYTHON_MODULE_INIT(name) \
void BOOST_PP_CAT(init_module_,name)(); \
extern "C" BOOST_SYMBOL_EXPORT _BOOST_PYTHON_MODULE_INIT(name)
# endif