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boost/python/converter/builtin_converters.hpp: 64-bit Windows special case to avoid getting a Python long for each std::size_t

[SVN r63696]
This commit is contained in:
Ralf W. Grosse-Kunstleve
2010-07-06 14:29:25 +00:00
parent e481c136e5
commit 14ea71e201

View File

@@ -122,9 +122,30 @@ BOOST_PYTHON_TO_INT(short)
BOOST_PYTHON_TO_INT(int)
BOOST_PYTHON_TO_INT(long)
// using Python's macro instead of Boost's - we don't seem to get the
// config right all the time.
# ifdef HAVE_LONG_LONG
# if defined(_MSC_VER) && defined(_WIN64)
/* Under 64-bit Windows std::size_t is "unsigned long long". To avoid
getting a Python long for each std::size_t the value is checked before
the conversion. A std::size_t is converted to a simple Python int
if possible; a Python long appears only if the value is too small or
too large to fit into a simple int. */
BOOST_PYTHON_TO_PYTHON_BY_VALUE(
signed BOOST_PYTHON_LONG_LONG,
( x < static_cast<signed BOOST_PYTHON_LONG_LONG>(
(std::numeric_limits<long>::min)())
|| x > static_cast<signed BOOST_PYTHON_LONG_LONG>(
(std::numeric_limits<long>::max)()))
? ::PyLong_FromLongLong(x)
: ::PyInt_FromLong(static_cast<long>(x)), &PyInt_Type)
BOOST_PYTHON_TO_PYTHON_BY_VALUE(
unsigned BOOST_PYTHON_LONG_LONG,
x > static_cast<unsigned BOOST_PYTHON_LONG_LONG>(
(std::numeric_limits<long>::max)())
? ::PyLong_FromUnsignedLongLong(x)
: ::PyInt_FromLong(static_cast<long>(x)), &PyInt_Type)
//
# elif defined(HAVE_LONG_LONG) // using Python's macro instead of Boost's
// - we don't seem to get the config right
// all the time.
BOOST_PYTHON_TO_PYTHON_BY_VALUE(signed BOOST_PYTHON_LONG_LONG, ::PyLong_FromLongLong(x), &PyLong_Type)
BOOST_PYTHON_TO_PYTHON_BY_VALUE(unsigned BOOST_PYTHON_LONG_LONG, ::PyLong_FromUnsignedLongLong(x), &PyLong_Type)
# endif