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callable_traits/example/is_constexpr/function_object.cpp

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C++

/*
Copyright Barrett Adair 2016
Distributed under the Boost Software License, Version 1.0.
(See accompanying file LICENSE.md or copy at http ://boost.org/LICENSE_1_0.txt)
*/
// NOTE: Due to non-compliance in MSVC, is_constexpr always
// returns std::false_type on that compiler, which causes
// the static asserts below to fail.
#include <type_traits>
#include <callable_traits/callable_traits.hpp>
namespace ct = callable_traits;
//this is a constexpr function object (non-templated)
struct zero {
constexpr auto operator()() const {
return 0;
}
};
static_assert(ct::is_constexpr<zero>(), "");
static_assert(ct::is_constexpr(zero{}), "");
//this is a constexpr function object (templated)
struct subtract {
// For callable_traits::is_constexpr, generic function objects
// only need to be SFINAE-friendly if the body of the operator()
// function accesses member names besides "type" and "value".
// Unary/binary operators and constructor calls are okay to use.
template<typename T1, typename T2>
constexpr auto operator()(T1, T2) const {
return T1{} - T2{};
}
};
static_assert(ct::is_constexpr<subtract>(), "");
static_assert(ct::is_constexpr(subtract{}), "");
//this is NOT a constexpr function object
struct add {
template<typename T1, typename T2>
auto operator()(T1, T2) const {
return T1{} + T2{};
}
};
static_assert(!ct::is_constexpr<add>(), "");
static_assert(!ct::is_constexpr(add{}), "");
/*
// The case below fails to compile, because lambdas are not trivially
// default constructible. (Note: This restriction also applies to the
// argument types). Error message: "Cannot perform constexpr checks
// with this type, because it is not trivially default constructible."
auto multiply = [](auto t1, auto t2) -> decltype(t1.value * t2.value) {
return t1.value * t2.value;
};
static_assert(!ct::is_constexpr<decltype(multiply)>(), "");
static_assert(!ct::is_constexpr(multiply), "");
*/
int main() {}