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Explicitly specify source type when compiling, so that there's no need to

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specify both name for C++ compiler and for C compiler, when initializing
non-default version.


[SVN r18775]
This commit is contained in:
Vladimir Prus
2003-06-11 10:27:46 +00:00
parent 876db3471e
commit 3ccadb869a
2 changed files with 4 additions and 4 deletions
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4
tools/gcc.jam
View File

@@ -75,12 +75,12 @@ flags gcc.compile INCLUDES <include> ;
actions compile.c++
{
$(NAME:E=g++) -Wall -ftemplate-depth-100 $(OPTIONS) -D$(DEFINES) -I"$(INCLUDES)" -c -o "$(<)" "$(>)"
$(NAME:E=g++) -x c++ -Wall -ftemplate-depth-100 $(OPTIONS) -D$(DEFINES) -I"$(INCLUDES)" -c -o "$(<)" "$(>)"
}
actions compile.c
{
$(NAME:E=gcc) -Wall $(OPTIONS) -D$(DEFINES) -I"$(INCLUDES)" -c -o "$(<)" "$(>)"
$(NAME:E=gcc) -x c -Wall $(OPTIONS) -D$(DEFINES) -I"$(INCLUDES)" -c -o "$(<)" "$(>)"
}

4
v2/tools/gcc.jam
View File

@@ -75,12 +75,12 @@ flags gcc.compile INCLUDES <include> ;
actions compile.c++
{
$(NAME:E=g++) -Wall -ftemplate-depth-100 $(OPTIONS) -D$(DEFINES) -I"$(INCLUDES)" -c -o "$(<)" "$(>)"
$(NAME:E=g++) -x c++ -Wall -ftemplate-depth-100 $(OPTIONS) -D$(DEFINES) -I"$(INCLUDES)" -c -o "$(<)" "$(>)"
}
actions compile.c
{
$(NAME:E=gcc) -Wall $(OPTIONS) -D$(DEFINES) -I"$(INCLUDES)" -c -o "$(<)" "$(>)"
$(NAME:E=gcc) -x c -Wall $(OPTIONS) -D$(DEFINES) -I"$(INCLUDES)" -c -o "$(<)" "$(>)"
}