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thread/doc/faq.xml
2004-07-01 14:01:51 +00:00

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<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE library PUBLIC "-//Boost//DTD BoostBook XML V1.0//EN"
"http://www.boost.org/tools/boostbook/dtd/boostbook.dtd" [
<!ENTITY % threads.entities SYSTEM "entities.xml">
%threads.entities;
]>
<section id="threads.faq" last-revision="$Date$">
<title>Frequently Asked Questions</title>
<qandaset>
<qandaentry>
<question>
<para>Are lock objects <link
linkend="threads.glossary.thread-safe">thread safe</link>?</para>
</question>
<answer>
<para><emphasis role="bold">No!</emphasis> Lock objects are not meant to
be shared between threads. They are meant to be short-lived objects
created on automatic storage within a code block. Any other usage is
just likely to lead to errors and won't really be of actual benefit anyway.
Share <link linkend="threads.concepts.mutexes">Mutexes</link>, not
Locks. For more information see the <link
linkend="threads.rationale.locks">rationale</link> behind the
design for lock objects.</para>
</answer>
</qandaentry>
<qandaentry>
<question>
<para>Why was &Boost.Threads; modeled after (specific library
name)?</para>
</question>
<answer>
<para>It wasn't. &Boost.Threads; was designed from scratch. Extensive
design discussions involved numerous people representing a wide range of
experience across many platforms. To ensure portability, the initial
implements were done in parallel using POSIX Threads and the Win32
threading API. But the &Boost.Threads; design is very much in the spirit
of C++, and thus doesn't model such C based APIs.</para>
</answer>
</qandaentry>
<qandaentry>
<question>
<para>Why wasn't &Boost.Threads; modeled after (specific library
name)?</para>
</question>
<answer>
<para>Existing C++ libraries either seemed dangerous (often failing to
take advantage of prior art to reduce errors) or had excessive
dependencies on library components unrelated to threading. Existing C
libraries couldn't meet our C++ requirements, and were also missing
certain features. For instance, the WIN32 thread API lacks condition
variables, even though these are critical for the important Monitor
pattern &cite.SchmidtStalRohnertBuschmann;.</para>
</answer>
</qandaentry>
<qandaentry>
<question>
<para>Why do <link linkend="threads.concepts.mutexes">Mutexes</link>
have noncopyable semantics?</para>
</question>
<answer>
<para>To ensure that <link
linkend="threads.glossary.deadlock">deadlocks</link> don't occur. The
only logical form of copy would be to use some sort of shallow copy
semantics in which multiple mutex objects could refer to the same mutex
state. This means that if ObjA has a mutex object as part of its state
and ObjB is copy constructed from it, then when ObjB::foo() locks the
mutex it has effectively locked ObjA as well. This behavior can result
in deadlock. Other copy semantics result in similar problems (if you
think you can prove this to be wrong then supply us with an alternative
and we'll reconsider).</para>
</answer>
</qandaentry>
<qandaentry>
<question>
<para>How can you prevent <link
linkend="threads.glossary.deadlock">deadlock</link> from occurring when
a thread must lock multiple mutexes?</para>
</question>
<answer>
<para>Always lock them in the same order. One easy way of doing this is
to use each mutex's address to determine the order in which they are
locked. A future &Boost.Threads; concept may wrap this pattern up in a
reusable class.</para>
</answer>
</qandaentry>
<qandaentry>
<question>
<para>Don't noncopyable <link
linkend="threads.concepts.mutexes">Mutex</link> semantics mean that a
class with a mutex member will be noncopyable as well?</para>
</question>
<answer>
<para>No, but what it does mean is that the compiler can't generate a
copy constructor and assignment operator, so they will have to be coded
explicitly. This is a <emphasis role="bold">good thing</emphasis>,
however, since the compiler generated operations would not be <link
linkend="threads.glossary.thread-safe">thread-safe</link>. The following
is a simple example of a class with copyable semantics and internal
synchronization through a mutex member.</para>
<programlisting>
class counter
{
public:
// Doesn't need synchronization since there can be no references to *this
// until after it's constructed!
explicit counter(int initial_value)
: m_value(initial_value)
{
}
// We only need to synchronize other for the same reason we don't have to
// synchronize on construction!
counter(const counter&amp; other)
{
boost::mutex::scoped_lock scoped_lock(other.m_mutex);
m_value = other.m_value;
}
// For assignment we need to synchronize both objects!
const counter&amp; operator=(const counter&amp; other)
{
if (this == &amp;other)
return *this;
boost::mutex::scoped_lock lock1(&amp;m_mutex &lt; &amp;other.m_mutex ? m_mutex : other.m_mutex);
boost::mutex::scoped_lock lock2(&amp;m_mutex &gt; &amp;other.m_mutex ? m_mutex : other.m_mutex);
m_value = other.m_value;
return *this;
}
int value() const
{
boost::mutex::scoped_lock scoped_lock(m_mutex);
return m_value;
}
int increment()
{
boost::mutex::scoped_lock scoped_lock(m_mutex);
return ++m_value;
}
private:
mutable boost::mutex m_mutex;
int m_value;
};
</programlisting>
</answer>
</qandaentry>
<qandaentry>
<question>
<para>How can you lock a <link
linkend="threads.concepts.mutexes">Mutex</link> member in a const member
function, in order to implement the Monitor Pattern?</para>
</question>
<answer>
<para>The Monitor Pattern &cite.SchmidtStalRohnertBuschmann; mutex
should simply be declared as mutable. See the example code above. The
internal state of mutex types could have been made mutable, with all
lock calls made via const functions, but this does a poor job of
documenting the actual semantics (and in fact would be incorrect since
the logical state of a locked mutex clearly differs from the logical
state of an unlocked mutex). Declaring a mutex member as mutable clearly
documents the intended semantics.</para>
</answer>
</qandaentry>
<qandaentry>
<question>
<para>Why supply <classname>boost::condition</classname> variables rather than
event variables?</para>
</question>
<answer>
<para>Condition variables result in user code much less prone to <link
linkend="threads.glossary.race-condition">race conditions</link> than
event variables. See <xref linkend="threads.rationale.events" />
for analysis. Also see &cite.Hoare74; and &cite.SchmidtStalRohnertBuschmann;.
</para>
</answer>
</qandaentry>
<qandaentry>
<question>
<para>Why isn't thread cancellation or termination provided?</para>
</question>
<answer>
<para>There's a valid need for thread termination, so at some point
&Boost.Threads; probably will include it, but only after we can find a
truly safe (and portable) mechanism for this concept.</para>
</answer>
</qandaentry>
<qandaentry>
<question>
<para>Is it safe for threads to share automatic storage duration (stack)
objects via pointers or references?</para>
</question>
<answer>
<para>Only if you can guarantee that the lifetime of the stack object
will not end while other threads might still access the object. Thus the
safest practice is to avoid sharing stack objects, particularly in
designs where threads are created and destroyed dynamically. Restrict
sharing of stack objects to simple designs with very clear and
unchanging function and thread lifetimes. (Suggested by Darryl
Green).</para>
</answer>
</qandaentry>
<qandaentry>
<question>
<para>Why has class semaphore disappeared?</para>
</question>
<answer>
<para>Semaphore was removed as too error prone. The same effect can be
achieved with greater safety by the combination of a mutex and a
condition variable.</para>
</answer>
</qandaentry>
</qandaset>
</section>