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175 lines
4.0 KiB
Plaintext
175 lines
4.0 KiB
Plaintext
How Runtime Polymorphism is expressed in Boost.Python:
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-----------------------------------------------------
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struct A { virtual std::string f(); virtual ~A(); };
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std::string call_f(A& x) { return x.f(); }
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struct B { virtual std::string f() { return "B"; } };
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struct Bcb : B
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{
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Bcb(PyObject* self) : m_self(self) {}
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virtual std::string f() { return call_method<std::string>(m_sef, "f"); }
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static std::string f_default(B& b) { return b.B::f(); }
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PyObject* m_self;
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};
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struct C : B
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{
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virtual std::string f() { return "C"; }
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};
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>>> class D(B):
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... def f():
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... return 'D'
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...
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>>> class E(B): pass
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...
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When we write, "invokes B::f non-virtually", we mean:
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void g(B& x) { x.B::f(); }
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This will call B::f() regardless of the dynamic type of x. Any other
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way of invoking B::f, including through a function pointer, is a
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"virtual invocation", and will call the most-derived override of f().
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Case studies
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C++\Python class
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\___A_____B_____C_____D____E___
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A | 1
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B | 2 3
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Bcb | 4 5 6
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C | 7 8
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1. Simple case
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2. Python A holds a B*. Probably won't happen once we have forced
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downcasting.
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Requires:
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x.f() -> 'B'
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call_f(x) -> 'B'
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Implies: A.f invokes A::f() (virtually or otherwise)
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3. Python B holds a B*.
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Requires:
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x.f() -> 'B'
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call_f(x) -> 'B'
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Implies: B.f invokes B::f (virtually or otherwise)
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4. B constructed from Python
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Requires:
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x.f() -> 'B'
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call_f(x) -> 'B'
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Implies: B.f invokes B::f non-virtually. Bcb::f invokes B::f
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non-virtually.
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Question: Does it help if we arrange for Python B construction to
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build a true B object? Then this case doesn't arise.
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5. D is a Python class derived from B
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Requires:
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x.f() -> 'D'
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call_f(x) -> 'D'
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Implies: Bcb::f must invoke call_method to look up the Python
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method override, otherwise call_f wouldn't work.
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6. E is like D, but doesn't override f
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Requires:
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x.f() -> 'B'
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call_f(x) -> 'B'
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Implies: B.f invokes B::f non-virtually. If it were virtual, x.f()
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would cause infinite recursion, because we've already
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determined that Bcb::f must invoke call_method to look up
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the Python method override.
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7. Python B object holds a C*
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Requires:
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x.f() -> 'C'
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call_f(x) -> 'C'
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Implies: B.f invokes B::f virtually.
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8. C object constructed from Python
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Requires:
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x.f() -> 'C'
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call_f(x) -> 'C'
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Implies: nothing new
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------
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Total implications:
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2: A.f invokes A::f() (virtually or otherwise)
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3: B.f invokes B::f (virtually or otherwise)
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4: B.f invokes B::f non-virtually. Bcb::f invokes B::f non-virtually
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6: B.f invokes B::f non-virtually.
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7: B.f invokes B::f virtually.
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5: Bcb::f invokes call_method to look up the Python method
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Though (4) is avoidable, clearly 6 and 7 are not, and they
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conflict. The implication is that B.f must choose its behavior
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according to the type of the contained C++ object. If it is Bcb, a
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non-virtual call to B::f must occur. Otherwise, a virtual call to B::f
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must occur. This is essentially the same scheme we had with
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Boost.Python v1.
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Note: in early versions of Boost.Python v1, we solved this problem by
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introducing a new Python class in the hierarchy, so that D and E
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actually derive from a B', and B'.f invokes B::f non-virtually, while
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B.f invokes B::f virtually. However, people complained about the
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artificial class in the hierarchy, which was revealed when they tried
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to do normal kinds of Python introspection.
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-------
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Assumption: we will have a function which builds a virtual function
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dispatch callable Python object.
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make_virtual_function(pvmf, default_impl, call_policies, dispatch_type)
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Pseudocode:
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Get first argument from Python arg tuple
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if it contains /only/ dispatch_type
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call default_impl
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else
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call through pvmf
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