]>

beta (a, b) = B (a, b) = \frac{Γ (a) Γ (b)}{Γ (a + b)}

beta (a, b) = {(\frac{a + g - 0.5}{a + b + g - 0.5})}^{a - 0.5} {(\frac{b + g - 0.5}{a + b + g - 0.5})}^{b} \sqrt{\frac{e}{b + g - 0.5}} \frac{L (a) L (b)}{L (c)}

beta (a, b) = {(\frac{a + g - 0.5}{a + b + g - 0.5})}^{a - b - 0.5} {(\frac{(a + g - 0.5) (b + g - 0.5)}{{(a + b + g - 0.5)}^{2}})}^{b} \sqrt{\frac{e}{b + g - 0.5}} \frac{L (a) L (b)}{L (c)}

beta (a, b) = \frac{(a + b)}{b} beta (a, b + 1)

beta (a, b) = \frac{(a + b) (a + b + 1)}{a b} beta (a + 1, b + 1)

i f a ≫ b a n d a + b = a t h e n : b e t a (a, b) = Γ (b)

if a = 1 then: beta (a, b) = \frac{1}{b}

e^{l c - l a - l b} {(\frac{l a}{l c})}^{a} {(\frac{l b}{l c})}^{b}